Integrand size = 21, antiderivative size = 55 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=\frac {\cot ^3(c+d x)}{3 a d}+\frac {\cot ^5(c+d x)}{5 a d}-\frac {\csc ^5(c+d x)}{5 a d} \]
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Time = 0.19 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3957, 2918, 2686, 30, 2687, 14} \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=\frac {\cot ^5(c+d x)}{5 a d}+\frac {\cot ^3(c+d x)}{3 a d}-\frac {\csc ^5(c+d x)}{5 a d} \]
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Rule 14
Rule 30
Rule 2686
Rule 2687
Rule 2918
Rule 3957
Rubi steps \begin{align*} \text {integral}& = -\int \frac {\cot (c+d x) \csc ^3(c+d x)}{-a-a \cos (c+d x)} \, dx \\ & = -\frac {\int \cot ^2(c+d x) \csc ^4(c+d x) \, dx}{a}+\frac {\int \cot (c+d x) \csc ^5(c+d x) \, dx}{a} \\ & = -\frac {\text {Subst}\left (\int x^4 \, dx,x,\csc (c+d x)\right )}{a d}-\frac {\text {Subst}\left (\int x^2 \left (1+x^2\right ) \, dx,x,-\cot (c+d x)\right )}{a d} \\ & = -\frac {\csc ^5(c+d x)}{5 a d}-\frac {\text {Subst}\left (\int \left (x^2+x^4\right ) \, dx,x,-\cot (c+d x)\right )}{a d} \\ & = \frac {\cot ^3(c+d x)}{3 a d}+\frac {\cot ^5(c+d x)}{5 a d}-\frac {\csc ^5(c+d x)}{5 a d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(116\) vs. \(2(55)=110\).
Time = 0.68 (sec) , antiderivative size = 116, normalized size of antiderivative = 2.11 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=-\frac {\csc (c) \csc ^3(c+d x) \sec (c+d x) (240 \sin (c)-96 \sin (d x)-54 \sin (c+d x)-18 \sin (2 (c+d x))+18 \sin (3 (c+d x))+9 \sin (4 (c+d x))-32 \sin (c+2 d x)+32 \sin (2 c+3 d x)+16 \sin (3 c+4 d x))}{960 a d (1+\sec (c+d x))} \]
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Time = 0.53 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.09
method | result | size |
parallelrisch | \(\frac {-3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}-5 \cot \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}-10 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}-30 \cot \left (\frac {d x}{2}+\frac {c}{2}\right )}{240 d a}\) | \(60\) |
derivativedivides | \(\frac {-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{5}-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}-\frac {2}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {1}{3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}}{16 d a}\) | \(62\) |
default | \(\frac {-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{5}-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}-\frac {2}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {1}{3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}}{16 d a}\) | \(62\) |
norman | \(\frac {-\frac {1}{48 a d}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{8 d a}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{24 d a}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{80 d a}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}\) | \(79\) |
risch | \(\frac {4 i \left (15 \,{\mathrm e}^{4 i \left (d x +c \right )}+6 \,{\mathrm e}^{3 i \left (d x +c \right )}+2 \,{\mathrm e}^{2 i \left (d x +c \right )}-2 \,{\mathrm e}^{i \left (d x +c \right )}-1\right )}{15 a d \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{5} \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )^{3}}\) | \(82\) |
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Time = 0.25 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.62 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=-\frac {2 \, \cos \left (d x + c\right )^{4} + 2 \, \cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )^{2} - 3 \, \cos \left (d x + c\right ) - 3}{15 \, {\left (a d \cos \left (d x + c\right )^{3} + a d \cos \left (d x + c\right )^{2} - a d \cos \left (d x + c\right ) - a d\right )} \sin \left (d x + c\right )} \]
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\[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=\frac {\int \frac {\csc ^{4}{\left (c + d x \right )}}{\sec {\left (c + d x \right )} + 1}\, dx}{a} \]
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Time = 0.20 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.75 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=-\frac {\frac {\frac {10 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}}{a} + \frac {5 \, {\left (\frac {6 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + 1\right )} {\left (\cos \left (d x + c\right ) + 1\right )}^{3}}{a \sin \left (d x + c\right )^{3}}}{240 \, d} \]
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Time = 0.32 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.35 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=-\frac {\frac {5 \, {\left (6 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}}{a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3}} + \frac {3 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 10 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3}}{a^{5}}}{240 \, d} \]
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Time = 13.99 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.09 \[ \int \frac {\csc ^4(c+d x)}{a+a \sec (c+d x)} \, dx=-\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+30\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+5}{240\,a\,d\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3} \]
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